2x^2+x-13=-4x-12

Solution for 2x^2+x-13=-4x-12 equation:

2x^2+x-13=-4x-12

We move all terms to the left:

2x^2+x-13-(-4x-12)=0

We get rid of parentheses

2x^2+x+4x+12-13=0

We add all the numbers together, and all the variables

2x^2+5x-1=0

a = 2; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·2·(-1)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{33}}{2*2}=\frac{-5-\sqrt{33}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{33}}{2*2}=\frac{-5+\sqrt{33}}{4}
$